1.5=0.25x^2+0.2x

Solution for 1.5=0.25x^2+0.2x equation:

1.5=0.25x^2+0.2x

We move all terms to the left:

1.5-(0.25x^2+0.2x)=0

We get rid of parentheses

-0.25x^2-0.2x+1.5=0

a = -0.25; b = -0.2; c = +1.5;
Δ = b2-4ac
Δ = -0.22-4·(-0.25)·1.5
Δ = 1.54
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.2)-\sqrt{1.54}}{2*-0.25}=\frac{0.2-\sqrt{1.54}}{-0.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.2)+\sqrt{1.54}}{2*-0.25}=\frac{0.2+\sqrt{1.54}}{-0.5}
$